Tuesday, December 6, 2011

What equation would i use to solve this problem?

One swimmer in a relay race has .47 sec lead and is swimming at a constant speed of 3.28 m/s. The swimmer has 55.1 m to swim before reaching the end of the pool A second swimmer moves in the same direction as the leader. What constant speed must the second swimmer have in order to catch up to the leader at the end of the pool in m/s?|||First, solve for t, which is the number of seconds it will take the lead swimmer to reach the end of the pool:





55.1 = 3.28 * t


t = 16.8 seconds





Then, you will solve for the speed of the second swimmer now that you know both the distance the swimmer must travel and how much time allotted to do it in:





v (for velocity) = 55.1 m / (16.8 - 0.47)


Note that you subtract 0.47 seconds from the time it will take the first swimmer to reach the end of the pool because the second swimmer must do this in less time.





v = 55.1m/16.33s


v = 3.37 m/s|||The second swimmer needs to swim 55.1 m to catch up. But he needs to do this in less time, since he has already lost 0.47 seconds of start....





The first swimmer will take (55.1-0.47*3.28)/3.28 = 16.3 seconds to finish the balance lap.





First swimmer's speed should be 55.1/16.3 = 3.38 m/s ...ANSWER

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